Discounting the momentum of the Earth as it circles the Sun, the 26Kg car is stationary, therefor not generating any momentum. while the 9Kg car is traveling at 351 mph (mp/h) (Actual movement). Weight has no bearing on the equation, except that they bot have to have some weight for gravity to hold them on the surface. The real question is who drives a 26Kg, or a 9Kg car?
So, 26Kg*0 is bigger or smaller than 9Kg*561Km/hr (switched miles to km's) ?
Huh, anybody got an answer?
How much is something times Zero?
The answer is the 9Kg car.
And don't get funny with me about the 26kg car at rest on the surface of Earth actually travelling at 1000mi/hr because of the rotation of the Earth, and the OTHER car is actually going west (against the rotation of the Earth), so its momentum is lower. Sheesh. KISS (=Keep It Simple, Stupid).
Momentum is mass times velocity (P=M*V)
So, 26Kg*0 is bigger or smaller than 9Kg*561Km/hr (switched miles to km's) ?
Huh, anybody got an answer?
How much is something times Zero?
The answer is the 9Kg car.
And don't get funny with me about the 26kg car at rest on the surface of Earth actually travelling at 1000mi/hr because of the rotation of the Earth, and the OTHER car is actually going west (against the rotation of the Earth), so its momentum is lower. Sheesh. KISS (=Keep It Simple, Stupid).
e = 1/2mv2