We are brave sailors always riding the sea;
We are less than one hundred but as tough as can be;
We sleep in three bunkers on top of each other;
Our numbers double from one bunker to another;
We dance in joy all through the night;
In groups of fives under the moonlight;
Last night twelve of us were swallowed by waves;
Leaving alive more than two third of the braves;
Still we continue the journey refusing to fail;
So tell me how many of us are left to sail?
Can you solve the answer?
Will give answer in a day or two...IF NEEDED! >_<
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1. From line 2: Total number of sailors is <100.
2. From lines 3 & 4: Let number of sailors sleeping in bunker 1 be X, then number of sailors sleeping in bunker 2 is 2X and in bunker 3 is 4X,
i.e. Total number of sailors = X+2X+4X = 7X and thus it is a multiple of 7.
3. From line 6: dancing in groups of fives means the total number is a product of 5.
4. From lines 7 & 8: 12 of the sailors drowned in the sea, leaving more than two third of the sailors alive, so the total number is > 36 (3 * 12).
Summing up all the above given information, the total number of sailors is <100 and >36, it divides by 7 and 5, which adds up to the total number of 70 sailors.
Since 12 of the 70 sailors died in the sea, there are 58 sailors left to continue the journey.
Thanks susan. :)
Thanks Matt. :)
:-)
Thanks Philo. :)
hehehe!
Thanks Vinny. :)
HAHAHA!
Thanks America. :)
Thanks Warren. :)
Why did I reply to this post again?
Here's a cat picture:
Algebra.... dang it's a beaotch...........!!
I was going to college.... and had to drop that class as not not take
an F...... I was carrying to much at that time.....
I feel your pain.... made me laugh outloud.... thank ya'...
HAHAHA!
Thanks chris. :)